print('{0:b}'.format(3))        # '11'
print('{0:8b}'.format(3))       # '      11'
print('{0:08b}'.format(3))      # '00000011'

def int2bin(integer, digits):
    if integer >= 0:
        return bin(integer)[2:].zfill(digits)
    else:
        return bin(2**digits + integer)[2:]
print(int2bin(3, 6))            # '000011'

integer = 7
bit_count = 5
print(f'{integer:0{bit_count}b}') # 0 filled

# The int is 37
print("{0:b}".format(37))
# Output - '100101'

number = 5
print('The binary equivalent of 5 is:', bin(number))

# output - The binary equivalent of 5 is: 0b101
# "0b" indicates that this is a binary number
# 101 is the number (2**2 * 1) + (2**1 * 0) + (2**0 * 1) = 5