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write a bash program to print a given number in reverse order Code Example
write a bash program to print a given number in reverse order 
n=123465
sd=0
rev=0
while [ $n -gt 0 ]
do
    sd=$(( $n % 10 ))
    rev=$(( $rev * 10 + $sd ))
    n=$(( $n / 10 ))
done
echo "Reverse number of entered digit is $rev"
Source: unix.stackexchange.com
write a bash program to print a given number in reverse order 
1
1
1
1
1
1
1
1
1
1



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Type:
 Code Example
Category:
 Coding
Sub Category:
 Code Example
Uploaded by:
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Horje