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numpy np sign change in df pandas zero crossing Code Example
numpy np sign change in df pandas zero crossing 
import numpy
a = [1, 2, 1, 1, -3, -4, 7, 8, 9, 10, -2, 1, -3, 5, 6, 7, -10]
zero_crossings = numpy.where(numpy.diff(numpy.sign(a)))[0]
Source: stackoverflow.com
numpy np sign change in df pandas zero crossing 
> zero_crossings
array([ 3,  5,  9, 10, 11, 12, 15])
Source: stackoverflow.com



Python

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