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The remquo() function in C is part of the standard math library <math.h> and is used to compute the remainder and part of the quotient of the division of two floating-point numbers. This function is particularly useful when we need both the remainder and some information about the quotient simultaneously for further calculations.
Syntax of remquo() in Cdouble remquo(double x, double y, int *quo); Parameters of remquo() in CThe remquo() function in C takes the following parameters:
- x: The dividend, a floating-point number.
- y: The divisor, a floating-point number.
- quo: A pointer to an integer where part of the quotient of x divided by y will be stored.
Return Value of remquo() in CThe remquo() function returns the remainder of the division of two floating-point numbers (i.e. division of x/y). The remainder is computed such that:
remainder = x − n × y Here, n is the integer quotient rounded towards zero.
Examples of remquo() Function in C LanguageThe following examples illustrates how we can use the remquo() function in C language.
Example 1The following program demonstrates how to calculate the remainder and part of the quotient of the division of two given numbers using the remquo() function in C.
C
// C Program to calculate the remainder and part of the
// quotient using remquo() function
#include <math.h>
#include <stdio.h>
int main()
{
// Initialize variables to take the input from the user
// and store the results
double x, y, remainder;
int quo;
// Take the input from the user
printf("Enter the dividend: ");
scanf("%lf", &x);
printf("Enter the divisor: ");
scanf("%lf", &y);
// Calculate the remainder and part of the quotient of
// the division of x by y
remainder = remquo(x, y, &quo);
// Print the remainder and part of the quotient
printf("The remainder of %.2lf divided by %.2lf is: "
"%.2lf\n",
x, y, remainder);
printf("Part of the quotient is: %d\n", quo);
return 0;
}
Output
Enter the dividend: 25
Enter the divisor: 4
The remainder of 25.00 divided by 4.00 is: 1.00
Part of the quotient is: 6 Time Complexity: O(1)
Auxiliary Space: O(1)
Example 2The following program demonstrates how to find the remainder and part of the quotient for different data types in C.
C
// C program to calculate the remainder and part of the
// quotient of different data types in C using remquo()
// function
#include <math.h>
#include <stdio.h>
int main()
{
// Initialize variables of different data types
double x1 = 10.5, y1 = 5.5;
float x2 = 20.5f, y2 = 6.5f;
long double x3 = 30.5l, y3 = 7.5l;
int quo1, quo2, quo3;
// Calculate the remainder using the appropriate remquo
// function for each data type
// remquo function for double
double result1 = remquo(x1, y1, &quo1);
// remquof function for float
float result2 = remquof(x2, y2, &quo2);
// remquol function for long double
long double result3 = remquol(x3, y3, &quo3);
// Print the results
printf("The remainder of %.2f divided by %.2f is %.2f "
"and part of the quotient is %d\n",
x1, y1, result1, quo1);
printf("The remainder of %.2f divided by %.2f is %.2f "
"and part of the quotient is %d\n",
x2, y2, result2, quo2);
printf("The remainder of %.2Lf divided by %.2Lf is "
"%.2Lf and part of the quotient is %d\n",
x3, y3, result3, quo3);
return 0;
}
Output
The remainder of 10.50 divided by 5.50 is -0.50 and part of the quotient is 2
The remainder of 20.50 divided by 6.50 is 1.00 and part of the quotient is 3
The remainder of 30.50 divided by 7.50 is 0.50 and part of the quotient is 4 Time Complexity: O(1)
Auxiliary Space: O(1)
Note: The remquo() Function is available in three variants: remquo() for double, remquof() for float, and remquol() for long double.
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