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python how to count ever yfile in fodler Code Example
python how to count ever yfile in fodler 
def count_files(dir):
    return len([1 for x in list(os.scandir(dir)) if x.is_file()])
Source: stackoverflow.com
python how to count ever yfile in fodler 
import os
directory = 'mydirpath'

number_of_files = len([item for item in os.listdir(directory) if os.path.isfile(os.path.join(directory, item))])
Source: stackoverflow.com
python how to count ever yfile in fodler 
import os

list = os.listdir(dir) # dir is your directory path
number_files = len(list)
print number_files
Source: stackoverflow.com
python how to count ever yfile in fodler 
import os

file_count = sum(len(files) for _, _, files in os.walk(r'C:\Dropbox'))
print(file_count)
Source: stackoverflow.com
python how to count ever yfile in fodler 
import os
isfile = os.path.isfile
join = os.path.join

directory = 'mydirpath'
number_of_files = sum(1 for item in os.listdir(directory) if isfile(join(directory, item)))
Source: stackoverflow.com
python how to count ever yfile in fodler 
def directory(path,extension):
  list_dir = []
  list_dir = os.listdir(path)
  count = 0
  for file in list_dir:
    if file.endswith(extension): # eg: '.txt'
      count += 1
  return count
Source: stackoverflow.com
python how to count ever yfile in fodler 
import os

onlyfiles = next(os.walk(dir))[2] #dir is your directory path as string
print len(onlyfiles)
Source: stackoverflow.com
python how to count ever yfile in fodler 
import os
print len(os.listdir(os.getcwd()))
Source: stackoverflow.com
python how to count ever yfile in fodler 
import fnmatch

print len(fnmatch.filter(os.listdir(dirpath), '*.txt'))
Source: stackoverflow.com



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Type:
 Code Example
Category:
 Coding
Sub Category:
 Code Example
Uploaded by:
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Views:
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