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Spotify is a popular music streaming platform that uses data analysis and management to improve user experience and provide personalized content. Spotify heavily relies on SQL (Structured Query Language) to manage its vast database and derive valuable insights. Whether you’re preparing for a job interview at Spotify or aiming to sharpen your SQL skills, practicing with targeted questions is crucial. In this guide, we’ll explore 15 essential SQL interview questions tailored for Spotify, designed to help you understand the kinds of challenges you might face and how to tackle them effectively. ![]() Top 15 Spotify SQL Interview QuestionsHere are some of the most important SQL questions that might encounter in a Spotify interview Question 1: Top 5 Artists with Most Songs in Top 10 Global Chart Positions.Assuming there are three Spotify tables: ‘ To find the top 5 artists with the highest number of songs appearing in the Top 10 of the ‘global_chart_rank‘ table. The query should display the artist names in ascending order along with their song appearance counts. music_artists:
music_tracks:
global_chart_rank:
Query: WITH top_10_songs AS ( Output: ![]() Output Explanations: The query identifies the top 5 artists with the most songs in the top 10 global chart positions. It does so by counting song appearances in the top 10, ranking the artists by song count, and then selecting and sorting the top 5 artists alphabetically. This provides a clear view of the most successful artists based on chart performance. Question 2: What are the Differences Between Inner and Full Outer Join?An inner join and a full outer join are both types of ways to combine information from two or more tables in a database. The main difference between them is how they handle rows that don’t have matching values in both tables. Inner Join: An inner join returns only the rows that have matching values in both tables. Example: SELECT A.column1, B.column2 Full Outer Join: A full outer join returns all the rows from both tables. Where there are no matches, NULL values are used to fill in the gaps. Example: SELECT A.column1, B.column2 Question 3: Identify Spotify’s Most Frequent ListenersAssuming there are two tables: ‘members’ and ‘member_listen_history’, which contain information about the members and their listening history, respectively. Write a query to identify the top 5 members who have listened to the most unique tracks in the last 30 days. Display the top 5 member names in ascending order of their member_id, along with the count of unique tracks they have listened to. Assume today’s date is ‘2023-03-22‘.
|
member_id | member_name | registration_date | |
---|---|---|---|
101 | alice | 2021-10-02 | [email protected] |
102 | bob | 2022-05-22 | [email protected] |
103 | charlie | 2022-01-01 | [email protected] |
104 | dave | 2021-07-15 | [email protected] |
105 | eve | 2021-12-24 | [email protected] |
member_listen_history
Table:listen_id | member_id | listen_date | track_id |
---|---|---|---|
1 | 101 | 2023-03-02 | 100 |
2 | 101 | 2023-03-02 | 101 |
3 | 101 | 2023-03-03 | 100 |
4 | 102 | 2023-03-03 | 103 |
5 | 102 | 2023-03-03 | 104 |
6 | 103 | 2023-03-03 | 100 |
7 | 104 | 2023-03-03 | 104 |
8 | 105 | 2023-03-03 | 100 |
SELECT m.member_id, m.member_name, COUNT(DISTINCT mlh.track_id) as total_unique_tracks_listened
FROM members m
INNER JOIN member_listen_history mlh ON m.member_id = mlh.member_id
WHERE mlh.listen_date BETWEEN '2023-02-22' AND '2023-03-22'
GROUP BY m.member_id, m.member_name
ORDER BY total_unique_tracks_listened DESC
LIMIT 5;
Output:
Output
Explantions:
This query identifies the top 5 members who have listened to the most unique tracks in the last 30 days. It joins the ‘members’ and ‘member_listen_history’ tables, counts the distinct tracks each member listened to, and then lists the top 5 members in descending order of their unique track count.
Let’s assume you are a Data Analyst at Spotify. You are given a data table named ‘musician_listens
'
containing daily listening counts for different musicians. The table has three columns: ‘musician_id
'
, ‘listen_date
'
, and ‘daily_listens
'
.
You are required to write a SQL query to calculate the 7-day rolling average of daily listens for each musician. The rolling average should be calculated for each day for each musician based on the previous 7 days (including the current day).
musician_listens Example Input:
musician_id | listen_date | daily_listens |
---|---|---|
1 | 2022-06-01 | 15000 |
1 | 2022-06-02 | 21000 |
1 | 2022-06-03 | 17000 |
2 | 2022-06-01 | 25000 |
2 | 2022-06-02 | 27000 |
2 | 2022-06-03 | 29000 |
Query:
SELECT
musician_id,
listen_date,
AVG(daily_listens) OVER (
PARTITION BY musician_id
ORDER BY listen_date
RANGE BETWEEN INTERVAL '6 days' PRECEDING AND CURRENT ROW
) AS rolling_avg_listens
FROM musician_listens
ORDER BY musician_id, listen_date;
Output:
Output
Explantion:
This query calculates the 7-day rolling average of daily listens for each musician. By using the AVG function with a window frame defined as the past 7 days (including the current day), the query provides insights into the trend of each musician’s daily listens over time.
Denormalization is a technique used to speed up database performance by intentionally adding duplicate data. Unlike normalization, which aims to minimize redundancy, denormalization sacrifices some data integrity in favor of faster data retrieval. This can be especially helpful when you need to combine information from different tables.
Write a SQL query to count the total number of users in the users
table.
Table: users
user_id | username | sign_up_date | |
---|---|---|---|
1001 | user1 | 2021-02-10 | [email protected] |
2002 | user2 | 2022-05-22 | [email protected] |
3003 | user3 | 2022-01-01 | [email protected] |
4004 | user4 | 2021-07-15 | [email protected] |
5005 | user5 | 2021-12-24 | [email protected] |
Table: user_listen_history
listen_id | user_id | listen_date | track_id |
---|---|---|---|
1 | 1001 | 2023-03-02 | 100 |
2 | 1001 | 2023-03-02 | 101 |
3 | 1001 | 2023-03-03 | 100 |
4 | 2002 | 2023-03-03 | 103 |
5 | 2002 | 2023-03-03 | 104 |
6 | 3003 | 2023-03-03 | 100 |
7 | 4004 | 2023-03-03 | 104 |
8 | 5005 | 2023-03-03 | 100 |
Query:
SELECT COUNT(*) AS total_users
FROM users;
Output:
Output
Explantion:
This query counts the total number of users in the ‘users’ table. By using the COUNT(*) function, it calculates the total number of rows in the table, representing the total number of registered users on the platform. The result is displayed in a column named total_users.
Write a SQL query to retrieve the usernames of users who signed up before January 1, 2022.
Query:
SELECT u.user_id, u.username, MAX(ulh.listen_date) AS "Most Recent Listen Date"
FROM users u
JOIN user_listen_history ulh ON u.user_id = ulh.user_id
GROUP BY u.user_id, u.username;
Output:
Output
Explantion:
This query retrieves the usernames of users who signed up before January 1, 2022. By joining the ‘users’ and ‘user_listen_history’ tables and grouping by user_id and username, it calculates the maximum listen date for each user. The result shows the usernames and their most recent listen dates.
Retrieve the usernames of users who listened to the song with track_id 100 on the listen_date ‘2023-03-03‘.
Query:
SELECT u.username
FROM users u
JOIN user_listen_history ulh ON u.user_id = ulh.user_id
WHERE ulh.track_id = 100
AND ulh.listen_date = '2023-03-03';
Output:
Output
Explantion:
This query identifies users who listened to the song with track_id 100 on March 3, 2023. By joining the ‘users’ and ‘user_listen_history’ tables and filtering for the specific track_id and listen_date, it retrieves the usernames of users who listened to that song on the specified date.
Identify the top 3 users who have listened to the most unique tracks.
SELECT u.username, COUNT(DISTINCT ulh.track_id) AS unique_tracks_listened
FROM users u
JOIN user_listen_history ulh ON u.user_id = ulh.user_id
GROUP BY u.username
ORDER BY unique_tracks_listened DESC
LIMIT 3;
Output:
Output
Explantion:
This query identifies the top 3 users who have listened to the most unique tracks. By joining the ‘users’ and ‘user_listen_history’ tables, counting the distinct track_ids for each user, and sorting them in descending order, it retrieves the usernames of the top 3 users with the highest unique track counts.
Spotify aims to gain insights into the average listening duration for each genre of music on their platform. As a data scientist, your task is to craft a SQL query to compute the average listening duration per genre.
Table: songs
song_id | song_name | genre_id | duration_seconds |
---|---|---|---|
1 | Song 1 | 1 | 180 |
2 | Song 2 | 2 | 240 |
3 | Song 3 | 1 | 200 |
4 | Song 4 | 3 | 300 |
5 | Song 5 | 4 | 220 |
Table: genres
genre_id | genre_name |
---|---|
1 | Pop |
2 | Rock |
3 | Hip Hop |
4 | Electronic |
Table: user_listen_history
listen_id | user_id | song_id | listen_duration | listen_date |
---|---|---|---|---|
1 | 1001 | 1 | 120 | 2023-03-01 |
2 | 1002 | 2 | 180 | 2023-03-01 |
3 | 1001 | 3 | 150 | 2023-03-02 |
4 | 1003 | 4 | 250 | 2023-03-02 |
5 | 1002 | 5 | 200 | 2023-03-03 |
Query:
SELECT g.genre_name, AVG(ulh.listen_duration) AS avg_listen_duration
FROM user_listen_history ulh
JOIN songs s ON ulh.song_id = s.song_id
JOIN genres g ON s.genre_id = g.genre_id
GROUP BY g.genre_name;
Output:
Output
Explantion:
This query computes the average listening duration for each music genre on Spotify. By joining the ‘user_listen_history’, ‘songs’, and ‘genres’ tables, it calculates the average listen duration per genre and presents the results showing each genre’s average listening duration.
Suppose Spotify wants to determine the total listening duration per genre for each user. Write a SQL query to calculate the total listening duration in seconds for each combination of user and genre, based on the user_listen_history
, songs
, and genres
tables provided.
Query:
SELECT ulh.user_id, g.genre_id, SUM(ulh.listen_duration) AS total_listen_duration
FROM user_listen_history ulh
JOIN songs s ON ulh.song_id = s.song_id
JOIN genres g ON s.genre_id = g.genre_id
GROUP BY ulh.user_id, g.genre_id;
Output:
Output
Explantion:
This query calculates the total listening duration per genre for each user on Spotify. By joining the ‘user_listen_history’, ‘songs’, and ‘genres’ tables and grouping by user and genre, it sums up the listen durations and presents the total listening duration for each combination of user and genre.
Query:
SELECT
ulh.*,
SUM(ulh.listen_duration) OVER (PARTITION BY ulh.user_id, s.genre_id) AS total_listen_duration_per_user_genre
FROM
user_listen_history ulh
JOIN
songs s ON ulh.song_id = s.song_id;
Output:
Output
Explanaton:
This query introduces a new column, ‘total_listen_duration_per_user_genre’, which calculates the total listening duration per user and genre combination. By using the SUM() OVER (PARTITION BY) clause, it sums the listen durations for each user’s interactions with songs of different genres, providing insights into user preferences.
HAVING
and WHERE
clauses in SQL queries. The HAVING
and WHERE
clauses are both used to filter rows in SQL queries, but they operate at different stages of the query execution.
HAVING
clauses: In simpler terms MSSQL, the HAVING clause is used to apply a filter on the result of GROUP BY based on the specified condition. The conditions are Boolean type i.e. use of logical operators (AND, OR). This clause was included in SQL as the WHERE keyword failed when we use it with aggregate expressions.As a Data Analyst at Spotify, suppose your team is interested in understanding the listening habits of users. You are provided with the following tables:
The following relationships hold:
user_id | username | sign_up_date | |
---|---|---|---|
1001 | user1 | 2021-02-10 | [email protected] |
2002 | user2 | 2022-05-22 | [email protected] |
3003 | user3 | 2022-01-01 | [email protected] |
4004 | user4 | 2021-07-15 | [email protected] |
5005 | user5 | 2021-12-24 | [email protected] |
track_id | track_name | artist_id | duration_seconds |
---|---|---|---|
1 | Song 1 | 1001 | 180 |
2 | Song 2 | 1002 | 240 |
3 | Song 3 | 1001 | 200 |
4 | Song 4 | 1003 | 300 |
5 | Song 5 | 1004 | 220 |
artist_id | artist_name |
---|---|
1001 | Artist 1 |
1002 | Artist 2 |
1003 | Artist 3 |
1004 | Artist 4 |
stream_id | user_id | track_id | stream_date |
---|---|---|---|
1 | 1001 | 1 | 2023-03-01 |
2 | 1002 | 2 | 2023-03-01 |
3 | 1001 | 3 | 2023-03-02 |
4 | 1003 | 4 | 2023-03-02 |
5 | 1002 | 5 | 2023-03-03 |
Query:
SELECT
u.username,
a.artist_name
FROM (
SELECT
us.user_id,
ti.artist_id,
COUNT(*) AS num_songs,
RANK() OVER (PARTITION BY us.user_id ORDER BY COUNT(*) DESC) as rank
FROM
user_streams us
JOIN
track_info ti ON us.track_id = ti.track_id
GROUP BY
us.user_id,
ti.artist_id
) AS sub_query
JOIN
user_info u ON u.user_id = sub_query.user_id
JOIN
artist_info a ON a.artist_id = sub_query.artist_id
WHERE
sub_query.rank = 1;
Output:
Output
Explantion:
This query determines each user’s favorite artist based on their listening habits. By ranking the number of songs each user has streamed for each artist and selecting the top-ranking artist for each user, it reveals the most listened-to artist for each user.
Query:
SELECT u.user_id, u.username, a.artist_name, COUNT(*) AS stream_count
FROM user_streams us
JOIN user_info u ON us.user_id = u.user_id
JOIN track_info ti ON us.track_id = ti.track_id
JOIN artist_info a ON ti.artist_id = a.artist_id
GROUP BY u.user_id, u.username, a.artist_name
ORDER BY stream_count DESC
LIMIT 1;
Output:
Output
Explantion:
This query identifies the user who has streamed the most songs by the same artist. By joining user information, song streams, track details, and artist information, it calculates the number of streams for each user-artist combination and retrieves the user with the highest stream count for a single artist.
Preparing for a SQL interview at Spotify involves mastering a range of SQL concepts and understanding how to apply them to real-world scenarios. By practicing these top 15 questions, you’ll be well-equipped to tackle SQL challenges and demonstrate your ability to manage and analyze data effectively. Remember, the key to success is consistent practice and a thorough understanding of both basic and advanced SQL topics.
Reffered: https://www.geeksforgeeks.org
Databases |
Type: | Geek |
Category: | Coding |
Sub Category: | Tutorial |
Uploaded by: | Admin |
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