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In this article we will discuss about star to delta conversion. We will first discuss about star and delta connections, current and voltage equations in these circuits. Then we will discuss about the differences between the star and delta connection. We will also discuss in detail the steps followed to derive the equations for conversion. In addition to this we will look into some solved examples that will help us understand the concept better. Later in the article we will discuss about the applications, advantages and disadvantages of this conversion. Table of Content What is Star and Delta Connection?In electrical circuit analysis there are certain type of complex circuits that have resistances connected in either series or parallel. These complex arrangements are usually connected in the T, Y, Delta or pi connections. Among these star and delta are some common types of connection. Star Connection CircuitStar connection circuit is the circuit where the three resistor in the circuit have a common point. The shape of the circuit can be in the shape of ‘Y’ and ‘T’ alphabet or we say star shape. The common point is grounded in most cases. This type of connections are required when there is need for a neutral point. It is mostly used in low and medium voltage distribution systems. ![]() Star Connection Delta Connection CircuitDelta connection is the type of connection where the three resistors are connected in a such way that they form a loop and they every two resistors have a common node. It is sometimes also in the shape of pi and mostly in shape of a triangle or can be referred to as delta. there is no common or neutral point available in the system. This connection type is used in high voltage transmission system. ![]() Delta Connection
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Star Circuit | Delta Circuit |
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In this type of circuit the all the three branches have a common node and branches initiate form this node. | In this type of circuit the three are connected in way that they form a loop and no common node is present. |
One terminal is common for all the branches in the circuit. | for every two branch one terminal remains common. |
[Tex]I_l=I_{ph} [/Tex] | [Tex]I_l=\sqrt3I_{ph} [/Tex] |
[Tex]V_l=\sqrt3 V_{ph} [/Tex] | [Tex]V_l=V_{ph} [/Tex] |
There is a neutral point present in the circuit | No neutral point is present in this type of circuit |
It receives less power than the supply. | It receives the full power |
Used in power transmission networks | Used in power distribution networks |
It can have both balanced and unbalanced load | It can only have balanced load. |
The resistances of star connection from delta connection are,
[Tex]R_A=\frac{R_1R_2}{R_1+R_2+R_3} \newline R_B=\frac{R_2R_3}{R_1+R_2+R_3} \newline R_C=\frac{R_3R_1}{R_1+R_2+R_3} [/Tex]
Star Connection
Now, to express the resistance of delta network in terms of star network we use the above equations. first we multiply set of two resistances and then add the three sets. After simplifying we will get the following equation.
[Tex]R_AR_B+R_BR_C+R_AR_C= \frac{R_1R_2R_3}{R_1+R_2+R_3} [/Tex] -(1)
Delta connection
The above equation(1) is now divided by the equation of RB ,
[Tex]\frac{R_AR_B+R_BR_C+R_AR_C}{R_B}=R_1 \newline \Longrightarrow R_1 =R_C+R_A+\frac{R_CR_A}{R_B} [/Tex]
The equation(1) is now divided by the equation of RC ,
[Tex]R_2 =R_A+R_B+\frac{R_AR_B}{R_C} [/Tex]
The equation(1) is now divide by the equation of RA ,
[Tex]R_3 =R_B+R_C+\frac{R_BR_C}{R_A} [/Tex]
The above three equation can be used to convert the star connection into delta connection.
1. Given a network of 9 resistors, find the equivalent resistance between point E and F.
The connection between A, B, C is in delta connection which is converted to its equivalent star connection with the common node O
[Tex]R_{AO}=\frac{4X6}{2+4+6}=2 \Omega \newline R_{BO}=\frac{2 X 6}{2+4+6}=1\Omega \newline R_{CO}=\frac{2 X 4}{2+4+6}=\frac{2}{3}\Omega [/Tex]
Star to Delta Conversion
The network can be further simplified by adding the resistances in series combination i.e. [Tex]R_{DO}=2+6=8 \Omega \newline R_{EO}= \frac{2}{3}+\frac{10}{3}=\frac{12}{3}=4\Omega \newline R_{FO}=7+1=8\Omega [/Tex]
Star to Delta Conversion
Now again the star connection in the inner part of the triangle is again converted into delta connection.
[Tex]R_1=4+8+\frac{8X4}{8}=16\Omega \newline R_2=8+8+\frac{8X8}{4}=32\Omega \newline R_3=8+4+\frac{8X4}{8}=16\Omega [/Tex]
Star to Delta Conversion
Now, we will apply parallel combination between the nodes DG and EI, EI and FH, FH and DG.
After that we will get the resistances as, [Tex]R_{DE}=8\Omega \newline R_{EF}=8\Omega \newline R_{FD}=\frac{32}{3}\Omega [/Tex]
Star to Delta conversion
The equivalent resistance between E and F will be
[Tex]R_{EF}=\frac{8 X(8+32/3)}{8+(8+32/3)}=\frac{8X56}{80}=5.6 \Omega [/Tex]
2. Find the current drawn from the 5v battery in the network given below.
Star to Delta Conversion
Let us consider some points in the given network as A, B, C, D and G. If we consider the points A, B, C, D we can see that it is in star connection with common point as B.
Star to Delta Conversion
Converting it into delta connection,
[Tex]R_1=2+2+\frac{2X2}{3}=\frac{16}{3} \Omega \newline R_2=2+3+\frac{2X3}{2}=8 \Omega \newline R_3=2+3+\frac{2X3}{2}=8 \Omega [/Tex]
Star to Delta Conversion
Now applying the parallel combination we get resistances as[Tex]R_{AD}=\frac{8}{9}\Omega \newline R_{AC}=\frac{16}{3}\Omega \newline R_{CD}=\frac{8}{3}\Omega [/Tex]
Star to Delta Conversion
Now we will use parallel combination and series combination to find an equivalent resistance,
[Tex]\frac{\frac{16}{3}X\frac{32}{9}}{\frac{16}{3}+\frac{32}{9}}=\frac{32}{15}\Omega \newline \frac{32}{15}+3=\frac{77}{15}\Omega [/Tex]
Star to Delta conversion
From the above circuit, we can calculate the value of I as [Tex]I=\frac{5}{77/15}=0.974A [/Tex]
There are some list of Advantages and Disadvantages of Star to Delta Conversion given below :
Star and Delta are two types of connections that are used to simplify and analyze complex electrical circuits. They are mainly implemented to the three phase networks and are widely used for power distribution and circuit design. The process of expressing the resistances of delta connection in terms of star provides three equations to convert a star network into a delta network. This technique is quite useful as it gives the flexibility of changing the connection type as the required parameters. Although it is very useful but there certain limitation as well which includes it being mostly limited to three phase networks.
The conversion is needed when we have to change the circuit design for simplification process. It is also done for optimizing the electrical circuit for various applications.
The main difference between in star and delta is the presence of common node in star connection and its absence in the delta connection. This will also make the shape of both the circuits different.
Star connection is preferred when there is a neutral point required or when the load is unbalanced. Delta connection is preferred in case of high voltage transmission and when common point is not required.
Reffered: https://www.geeksforgeeks.org
Electric Circuits |
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