Counting K-Length Strings with Fixed Character in a Unique String - Coding

Given a string S of length n containing distinct characters and a character C , the task is to count k-length strings that can be formed using characters from the string S, ensuring each string includes the specified character C, and no characters from the given string S are used more than once. Return the answer by taking modulo of 1e9 + 7.

Example:

Input: C = ‘a’, S = “abc”, k = 2
Output: 4
Explanation: All two-length strings are: {ab, ac, ba, bc, ca, cb}
All valid strings including character ‘C’ are: {ab, ac, ba, ca}

Input: C = ‘c’, S = “abcde”, k = 3
Output: 36

Approach:

Think about complement approach that is: Count of total two length strings – Count of two length string that doesn’t containing given character C.

Formula: ⁿC_k * k! – ^{(n – 1)}C_k * k!

nCk * k!: Select k elements from n characters (i.e, ⁿC_k) and permulte them (i.e, k!)

^{(n – 1)}C_k * k!: Assume given character is not present in S then selecting k elements from (n – 1) (i.e, ^(n-1)C_k) and permute them (k!)

Steps-by-step approach:

Initialize an array fact to store factorials.
Calculate factorials up to M using a loop.
Calculate a^b under modulus mod using binary exponentiation.
Calculate the modular multiplicative inverse of a under modulus mod.
Calculate “n choose r” (combination) under modulus mod.
Calculate the count of k-length strings containing character C from the given string S using above formula.

Below is the implementation of the above approach:

C++

#include <bits/stdc++.h>
using namespace std;
int const M
    = 1e6 + 10; // Define the maximum size of the array
long long const mod
    = 1e9 + 7; // Define the modulus for calculations
 
vector<long long> fact(M); // Initialize the factorial array
 
// Function to pre-calculate the factorial of numbers up to
// M
void preCalculateFact()
{
    fact[0] = 1; // 0! = 1
    fact[1] = 1; // 1! = 1
 
    // Calculate the factorial for the rest of the numbers
    for (int i = 2; i < M; i++) {
        fact[i] = (fact[i - 1] * i) % mod;
    }
}
 
// Function to calculate a^b under modulus mod using binary
// exponentiation
long long binaryExpo(long long a, long long b,
                     long long mod)
{
    long long ans = 1;
 
    while (b) {
        if (b & 1) {
            ans = (ans * a) % mod;
        }
        a = (a * a) % mod;
        b >>= 1;
    }
 
    return ans;
}
 
// Function to calculate the modular multiplicative inverse
// of a under modulus mod
long long modMultiInv(long long a, long long mod)
{
    return binaryExpo(a, mod - 2, mod);
}
 
// Function to calculate n choose r under modulus mod
int nCr(int n, int k)
{
    return (fact[n] * modMultiInv(fact[k], mod) % mod
            * modMultiInv(fact[n - k], mod) % mod)
           % mod;
}
 
// Function to solve the problem
int solve(int n, int k, char c, string& s)
{
    preCalculateFact(); // Pre-calculate the factorials
    return (nCr(n, k) * 1LL * fact[k])
           - (nCr(n - 1, k) * 1LL * fact[k]);
}
 
// Main function
int main()
{
    int n = 3; // Size of the string
    int k = 2; // Length of the strings to be formed
    char c = 'a'; // Character that must be included in the
                  // strings
 
    string s = "abc"; // Given string
 
    cout << solve(n, k, c, s); // Print the solution
 
    return 0;
}

Java

import java.util.*;
 
public class Main {
    static final int M = (int)1e6 + 10; // Define the maximum size of the array
    static final long mod = (long)1e9 + 7; // Define the modulus for calculations
    static long[] fact = new long[M]; // Initialize the factorial array
 
    // Function to pre-calculate the factorial of numbers up to M
    static void preCalculateFact() {
        fact[0] = 1; // 0! = 1
        fact[1] = 1; // 1! = 1
 
        // Calculate the factorial for the rest of the numbers
        for (int i = 2; i < M; i++) {
            fact[i] = (fact[i - 1] * i) % mod;
        }
    }
 
    // Function to calculate a^b under modulus mod using binary exponentiation
    static long binaryExpo(long a, long b, long mod) {
        long ans = 1;
 
        while (b > 0) {
            if ((b & 1) == 1) {
                ans = (ans * a) % mod;
            }
            a = (a * a) % mod;
            b >>= 1;
        }
 
        return ans;
    }
 
    // Function to calculate the modular multiplicative inverse of a under modulus mod
    static long modMultiInv(long a, long mod) {
        return binaryExpo(a, mod - 2, mod);
    }
 
    // Function to calculate n choose r under modulus mod
    static int nCr(int n, int k) {
        return (int)(((fact[n] * modMultiInv(fact[k], mod) % mod) * modMultiInv(fact[n - k], mod)) % mod);
    }
 
    // Function to solve the problem
    static int solve(int n, int k, char c, String s) {
        preCalculateFact(); // Pre-calculate the factorials
        return (int)((nCr(n, k) * 1L * fact[k]) - (nCr(n - 1, k) * 1L * fact[k]));
    }
 
    // Main function
    public static void main(String[] args) {
        int n = 3; // Size of the string
        int k = 2; // Length of the strings to be formed
        char c = 'a'; // Character that must be included in the strings
 
        String s = "abc"; // Given string
 
        System.out.println(solve(n, k, c, s)); // Print the solution
    }
}

C#

using System;
 
class Program
{
    const int M = 1000000 + 10; // Define the maximum size of the array
    const long Mod = 1000000007; // Define the modulus for calculations
    static long[] fact = new long[M]; // Initialize the factorial array
 
    // Function to pre-calculate the factorial of numbers up to M
    static void PreCalculateFact()
    {
        fact[0] = 1; // 0! = 1
        fact[1] = 1; // 1! = 1
 
        // Calculate the factorial for the rest of the numbers
        for (int i = 2; i < M; i++)
        {
            fact[i] = (fact[i - 1] * i) % Mod;
        }
    }
 
    // Function to calculate a^b under modulus mod using binary exponentiation
    static long BinaryExpo(long a, long b, long mod)
    {
        long ans = 1;
 
        while (b > 0)
        {
            if (b % 2 == 1)
            {
                ans = (ans * a) % mod;
            }
            a = (a * a) % mod;
            b >>= 1;
        }
 
        return ans;
    }
 
    // Function to calculate the modular multiplicative inverse of a under modulus mod
    static long ModMultiInv(long a, long mod)
    {
        return BinaryExpo(a, mod - 2, mod);
    }
 
    // Function to calculate n choose r under modulus mod
    static int nCr(int n, int k)
    {
        return (int)((fact[n] * ModMultiInv(fact[k], Mod) % Mod * ModMultiInv(fact[n - k], Mod) % Mod) % Mod);
    }
 
    // Function to solve the problem
    static int Solve(int n, int k, char c, string s)
    {
        PreCalculateFact(); // Pre-calculate the factorials
        return (int)((nCr(n, k) * 1L * fact[k]) - (nCr(n - 1, k) * 1L * fact[k]));
    }
 
    // Main function
    static void Main(string[] args)
    {
        int n = 3; // Size of the string
        int k = 2; // Length of the strings to be formed
        char c = 'a'; // Character that must be included in the strings
 
        string s = "abc"; // Given string
 
        Console.WriteLine(Solve(n, k, c, s)); // Print the solution
    }
}

Javascript

const mod = BigInt(1e9 + 7); // Define the modulus for calculations
const M = 1e6 + 10; // Define the maximum size of the array
 
const fact = new Array(M); // Initialize the factorial array
 
// Function to pre-calculate the factorial of numbers up to M
function preCalculateFact() {
    fact[0] = BigInt(1); // 0! = 1
    fact[1] = BigInt(1); // 1! = 1
 
    // Calculate the factorial for the rest of the numbers
    for (let i = 2; i < M; i++) {
        fact[i] = (fact[i - 1] * BigInt(i)) % mod;
    }
}
 
// Function to calculate a^b under modulus mod using binary exponentiation
function binaryExpo(a, b) {
    let ans = BigInt(1);
 
    while (b > BigInt(0)) {
        if (b & BigInt(1)) {
            ans = (ans * a) % mod;
        }
        a = (a * a) % mod;
        b >>= BigInt(1);
    }
 
    return ans;
}
 
// Function to calculate the modular multiplicative inverse of a under modulus mod
function modMultiInv(a) {
    return binaryExpo(a, mod - BigInt(2));
}
 
// Function to calculate n choose r under modulus mod
function nCr(n, k) {
    return (
        (fact[n] * modMultiInv(fact[k]) % mod) *
        modMultiInv(fact[n - k]) % mod
    ) % mod;
}
 
// Function to solve the problem
function solve(n, k, c, s) {
    preCalculateFact(); // Pre-calculate the factorials
    return (
        (nCr(n, k) * fact[k]) % mod -
        (nCr(n - 1, k) * fact[k]) % mod
    ) % mod;
}
 
const n = 3; // Size of the string
const k = 2; // Length of the strings to be formed
const c = 'a'; // Character that must be included in the strings
 
const s = "abc"; // Given string
 
console.log(solve(n, k, c, s).toString()); // Print the solution

Python3

mod = int(1e9 + 7)  # Define the modulus for calculations
M = int(1e6 + 10)   # Define the maximum size of the array
 
fact = [0] * M  # Initialize the factorial array
 
 
# Function to pre-calculate the factorial of numbers up to M
def pre_calculate_fact():
    fact[0] = 1  # 0! = 1
    fact[1] = 1  # 1! = 1
 
    # Calculate the factorial for the rest of the numbers
    for i in range(2, M):
        fact[i] = (fact[i - 1] * i) % mod
 
 
# Function to calculate a^b under modulus mod using binary exponentiation
def binary_expo(a, b, mod):
    ans = 1
 
    while b:
        if b & 1:
            ans = (ans * a) % mod
        a = (a * a) % mod
        b >>= 1
 
    return ans
 
 
# Function to calculate the modular multiplicative inverse of a under modulus mod
def mod_multi_inv(a, mod):
    return binary_expo(a, mod - 2, mod)
 
 
# Function to calculate n choose r under modulus mod
def nCr(n, k):
    return (fact[n] * mod_multi_inv(fact[k], mod) % mod
            * mod_multi_inv(fact[n - k], mod) % mod) % mod
 
 
# Function to solve the problem
def solve(n, k, c, s):
    pre_calculate_fact()  # Pre-calculate the factorials
    return (nCr(n, k) * fact[k]
            - nCr(n - 1, k) * fact[k])
 
 
# Main function
def main():
    n = 3  # Size of the string
    k = 2  # Length of the strings to be formed
    c = 'a'  # Character that must be included in the strings
 
    s = "abc"  # Given string
 
    print(solve(n, k, c, s))  # Print the solution
 
 
if __name__ == "__main__":
    main()

Output

Time Complexity: O(M), where M is size for storing factorial
Auxiliary Space: O(M)

Reffered: https://www.geeksforgeeks.org

Combinatorial

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Category:	Coding
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