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Program to Print Right Half Pyramid Pattern (Star Pattern)

Given an integer N, print N rows of right half pyramid pattern. In right half pattern of N rows, the first row has 1 star, second row has 2 stars and so on till the Nth row which has N stars. All the stars are left aligned.

rightHalfPyramid

Examples:

Input: 3
Output:
*
**
***

Input: 5
Output:
*
**
***
****
*****

Approach:

The problem can be solved using two nested loops. The outer loop will run for the rows and the inner loop will print the stars.

Step-by-step approach:

  • Run an outer loop from i = 1 to the number of rows.
    • Run an inner loop from j = 1 to i.
      • Print an asterisk in each iteration of the inner loop.
    • Print a newline character (“\n”) to move to the next row.
  • After N iterations, we will have the right half pyramid pattern.

Below is the implementation of the above approach:

C++

#include <iostream>
using namespace std;
 
int main()
{
    // Number of rows
    int N = 5;
 
    // Outer loop runs N times, once for each row
    for (int i = 1; i <= N; i++) {
        // Inner loop prints 'i' stars
        for (int j = 1; j <= i; j++) {
            cout << "*";
        }
        // Move to the next line
        cout << "\n";
    }
 
    return 0;
}

Java

import java.util.Scanner;
 
public class Main {
    public static void main(String[] args)
    {
 
        // Number of rows
        int N = 5;
 
        // Outer loop runs N times, once for each row
        for (int i = 1; i <= N; i++) {
            // Inner loop prints 'i' stars
            for (int j = 1; j <= i; j++) {
                System.out.print("*");
            }
            // Move to the next line
            System.out.println();
        }
    }
}

Python3

# Number of rows
N = 5
 
# Outer loop runs N times, once for each row
for i in range(1, N + 1):
    # Inner loop prints 'i' stars
    for j in range(1, i + 1):
        print("*", end="")
    # Move to the next line
    print()

C#

using System;
 
class Program
{
    static void Main()
    {
        // Number of rows
        int N = 5;
 
        // Outer loop runs N times, once for each row
        for (int i = 1; i <= N; i++)
        {
            // Inner loop prints 'i' stars
            for (int j = 1; j <= i; j++)
            {
                Console.Write("*");
            }
            // Move to the next line
            Console.WriteLine();
        }
    }
}

Javascript

// Number of rows
let N = 5;
 
// Outer loop runs N times, once for each row
for (let i = 1; i <= N; i++) {
    // Inner loop prints 'i' stars
    for (let j = 1; j <= i; j++) {
        process.stdout.write("*");
    }
    // Move to the next line
    console.log();
}

Output

*
**
***
****
*****

Time Complexity: O(N2), where N is the number of rows in the pattern.
Auxiliary Space: O(1)


 


Reffered: https://www.geeksforgeeks.org

Programming

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Type:
 Geek
Category:
 Coding
Sub Category:
 Tutorial
Uploaded by:
 Admin
Views:
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