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Cannizaro Reaction in organic chemistry is known for its duality and versatility. Cannizzaro’s reaction is named after its discoverer and founder, Stanislao Cannizzaro. The Cannizzaro reaction is a well-known chemical transformation that has fascinated scientists and researchers for generations. In this blog, we will explore the intricate mechanism of the Cannizzaro reaction that underlay redox reaction principles. We will also get to know how Cannizzaro’s reaction has an indelible mark on the chemical world and plays a crucial role in the synthesis of carboxylic acids and alcohols. Table of Content What is Cannizzaro’s Reaction?The Cannizzaro reaction is a chemical transformation in redox chemistry that involves the base-induced disproportionation of two molecules of a non-enolizable aldehyde to yield a carboxylic acid and a primary alcohol. In other words, one molecule of the aldehyde undergoes oxidation to form the corresponding carboxylic acid, while the other molecule undergoes reduction to form the corresponding primary alcohol. ![]() Cannizzaro Reaction Learn about Balancing Redox Reactions Examples of Cannizzaro ReactionThe example of cannizzaro reaction is shown in the image below: Here are a couple of examples where Cannizzaro reaction is used:
Mechanism of Cannizzaro ReactionThe mechanism of Cannizzaro reaction is process of getting one molecule of alcohol and one molecule of carbocyclic acid from two molecules of a given aldehyde. Below-mentioned are the steps of mechanics of Cannizzaro Reaction: Step 1: Nuceophilic AttackIn the very first step, the crbonyl group the aldehyde undergoes nucleophile attack from a nucleophile such as OH. This nucleophile attack produces anion having two negative charges as result. Step 2: Hydride TransferThe intermediate formed in step 1 is unstable and act as hydride transfer agent for another aldehyde molecule and reduce it. Thus the another aldehyde group get reduced to alkoxide ion while the intermediate that acted as hydride transfer agent becomes carboxylate anion. Step 3: Proton ExchangeIn the third and the final step, the alkoxide ion formed in step 2 gains proton from water thus resulting in the alcohol as the final product. After the workup of acid, the carboxylate ion get converted to carboxylic acid. Since, the acid is less basic than water hence, it can’t obtain proton from water. Crossed Cannizzaro ReactionThe Crossed Cannizzaro Reaction is a variation of Cannizzaro Reation in which two different aldehydes are reacted together and one of them must be non-enolizable. Here is a brief difference between Cannizzaro Reaction and Crossed Cannizzaro Reaction. Mechanism of Crossed Cannizzaro ReactionThe mechanism of crossed cannizzaro reaction involves the disproportionaion of two different aldeyhdes with one aldehyde acting as a reductant and the other aldehyde acting as an oxident:
Below is the chemical equation of crossed cannizzaro reaction between formaldehyde and benzaldehyde:
Cannizzarro vs Crossed Cannizzarro ReactionThe basic comparison between cannizzaro and crossed cannizzaro reaction is mentioned in the table below:
Applications of the Cannizzaro ReactionThe Cannizzaro Reaction has a variety of applications in the organic chemistry:
Also, Check Sample Questions on Cannizzaro ReactionQuestion 1: What is Cannizzaro Reaction in organic chemistry? Answer:
Question 2: What are the products formed in the Cannizzaro chemical reaction involving formaldehyde (HCHO)? Answer:
Question 3: Provide the balanced chemical equation of Cannizzaro reaction involving benzaldehyde. Answer:
Question 4: Discuss some practical applications of the Crossed Cannizzaro Reaction. Answer:
Question 5: Can ketones undergo the Cannizzaro reaction? Why or Why not? Answer:
FAQs on Cannizzaro Reaction1. What is Cannizzaro Reaction in Organic Chemistry?
2. How many Compounds give Cannizzaro Reaction?
3. Does Ketone udergoes Cannizzaro Reaction?
4. Is Cannizzaro a Redox Reaction?
5. What are the Limitations of Cannizzaro Reaction?
6. What is the Differnce between Cannizzaro and Crossed Cannizzaro Reaction?
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