Table of Content

• Lorentz Factor Definition
• Inertial Frame of Reference
• Non-Inertial Frame of Reference 
• Difference between Inertial Frame of Reference and Non-Inertial Fames of Reference
• Lorentz Transformation
• The formula for Lorentz transformation can be given as,
• Time Dilation
• Properties of Lorentz Factor
• Solved Examples on Lorentz Factor

Aspect	Inertial Frame of Reference	Non-Inertial Frame of Reference
Definition	Moves at constant speed or is stationary	Undergoes acceleration relative to an inertial frame.
Validity of Newton’s Laws	Newton’s laws of motion hold true	Newton’s laws of motion do not hold true
Pseudo Force Requirement	No requirement for pseudo forces	Pseudo forces are needed to apply Newton’s laws
Motion Characteristics	Uniform motion or at rest	Varying velocities or accelerations
Accelerometer Readings	Typically zero accelerations	Non-zero accelerations may be detected
Examples	Stationary platform, constant velocity motion	Circular motion, accelerating vehicle

Check: Inertial and Non-Inertial Frame of Reference

Lorentz Transformation

The Lorentz transformations are a one-parameter family of linear transformations from a frame in spacetime that is in a fixed position to a frame that is moving with constant speed. These transformations are named after a Dutch physicist, Hendrik Lorentz.

The formula for Lorentz transformation can be given as,

t’ = γ(t – (vx)/c²)

x’ = γ(x – vt)

y’ = y 

z’ = z

where, 
(t, x, y, z) and (t’, x’, y’, z’) are the coordinates of event in two frames.
v is restricted velocity to x-direction.
c is speed of light

Since the Galilean transformation cannot explain why observers traveling at various speeds measure different distances and experience events in a different sequence even if light travels at the same speed in all inertial reference frames, the Lorentz transformations were developed from it.

From the Galilean transformation, we can derive Lorentz transformation as,

x’ = a₁x + a₂t

y’ = y 

z’ = z

t’ = b₁x + b₂t

With speed v in non-inertial frame S, the origin of the inertial frame is x’ = 0. Let x = vt represent the position in non-inertial frame S at time t for the light beam.

Therefore, x’ = 0 = a₁x + a₂t ⇒ x = -(a₂/a₁) t = vt

where, 

a₂/a₁ = -v

Now, the above equation can be written as,

x’ = a₁x + a₂t = a₁(x + (a₂/a₁)t) = a₁ (x – vt)

a₁²(x – vt₂) + y’² + z’² – c²(b₁x + b₂t)² = x² + y² + z² – c²t²

a₁²x² – 2a₁²xvt + a₁²v²t² – c²b₁²x² – 2c²b₁b₂xt – c²b₂²t² = x² – c²t²

(a₁² – c²b₂)x² = x²  OR  a₁² – c²b₁² = 1

(a₁²v² – c²b₂²)t² = -c²t²  OR  c²b₂² – a₁²v² = c²

(2a₁²v + 2b₁b₂c²)xt = 0  OR  b₁b₂c² = -a₁²v

b₁²c² = a₁² – 1

b₂²c² = c² + a₁²v²

b₁²b₂²c⁴ = (a₁² – 1) (c² + a₁²v²) = a₁⁴v²

a₁²c² – c² + a⁴v² – a₁²v² = a₁⁴v²

a₁²c² – a₁²v² = c²

a₁²(c² – v²) = c²

a₁² = c²/(c² – v²) = 1/(1 – v²/c²)

a₂ = -v(1 / √(1 – v²/c²))

b₁²c² = (1/(1 – v²/c²) – 1)

b₁²c² = (1-(1 – v²/c²))/(1 – v²/c²) = (v²/c²)/(1-(v²/c²)) = v²/c²(1/1-(v²/c²))

b₁² = v²/c⁴ (1/1-(v²/c²))

b₁ = -v/c² (1/√(1-(v²/c²)))

b₂²c² = (c² + v²(1/1-(v²/c²)) = c²(1 – v²/c²) + v² / 1-(v²/c²) = c²-v²+v²/1-(v²/c²) = c² / 1 – (v²/c²)

b₂² = 1/1-(v²/c²)

b₂ = 1/√1-(v²/c²)  (b₂ is close to a₁)

γ = 1 / √1 – (v²/c²)

the equation can also be written as,

a₁ = γ

a₂ = -γv

b₁ = -(v/c²)γ

b₂ = γ

The final Equation of Lorentz transformation is: 

• x’ = γ(x – vt)
• y’ = y
• z’ = z
• t’ = γ(t – (v/c²)x)

Time Dilation

Either a difference in gravitational potential between their locations or the relative velocities between the two frames of reference produce time dilation (gravitational time dilation taken from general relativity). “Time dilation” describes the velocity-related effect, when it cannot be determined.

Assume that in the reference frame, the time interval between the events is denoted by the symbol Δt0 and is known as proper time or one-position time. In another reference frame (i.e. the observers’ reference frame) the time interval between two events is denoted by the symbol Δt. the observer time will always be higher than the proper time. This is what we refer to as time dilation.

The time dilation formula can be written as,

Δt = Δt₀ / √(1-(v/c)²)

where,
Δt is Observer time or two-position time
Δt₀ is Proper time or one position time
v is Relative velocity of two observers
c is the speed of light in a vacuum

Properties of Lorentz Factor

Following are the properties of Lorentz Factor

• The value of the Lorentz Factor is always greater than 1. (γ > 1)
• The Lorentz factor is very close to 1, If the clock speed (v) is slow in comparison to the speed of light (c).
• If the clock speed, v, approaches the speed of light, c, the Lorentz factor increases significantly.

Also, Check

• Relative Motion
• Special Theory of Relativity
• Lorentz Force

Solved Examples on Lorentz Factor

Problem 1: If the relative velocity between the two observers is 120 m/s, Determine the Lorentz factor. (Speed of light is 3 x 108 m/s).

Solution:

Given:

Relative Velocity (v) = 120 m/s

Speed of light (c) = 3 x 108 m/s

Therefore, Lorentz factor is given as,

γ = 1 / √(1-(v/c)²)

γ = 1 / √(1-(120/3 x 108)²)  

= 1 / √(1 – (14400 / 9 x 1016))

= 1 

Problem 2: If the relative velocity between the two observers is 300 m/s, Determine the Lorentz factor. (Speed of light is 2.99 x 108 m/s).

Solution:

Given:

Relative Velocity (v) = 300 m/s

Speed of light (c) = 2.99 x 108 m/s

Therefore, Lorentz factor is given as,

γ = 1 / √(1-(v/c)²)

γ = 1 / √(1 – (300/3 x 108)²)  

= 1 / √(1 – (90000 / 8.9401 x 1016))

= 1

Problem 3: The ratio of v to c is given as 26.7 x 10-8, Determine the Lorentz factor. (Speed of light is 2.99 x 108 m/s).

Solution:

Given:

The ratio of v to c (v/c) = β = 26.7 x 10-8

Therefore, Lorentz factor is given as,

γ = 1 / √(1-(v/c)²)

γ = 1 / √(1-(26.7 x 10^-8)²)  

= 1

Problem 4: If the time interval is 25 seconds and the observer velocity is 30,000 m/s, Find the relative time.

Solution:

Given,

Time interval (Δt₀) = 25 seconds

Observer velocity (v) = 30,000 m/s

Relative time Δt = Δt₀ / √(1 – v²/c²)

= 25 / √(1 – 30,000²/299,792,4582)

= 25 sec

Therefore, the relative time is 25 seconds.

Problem 5:  Find the relative time, If the time interval is 32 seconds and the observer velocity is 50,000 m/s.

Solution:

Given,

Time interval (Δt₀) = 32 seconds

Observer velocity (v) = 50,000 m/s

Relative time Δt = Δt₀ / √(1 – v²/c²)

= 32 / √(1 – 50,000²/299,792,4582)

= 32 sec

Therefore, the relative time is 32 seconds.

Lorentz Transformations-FAQs

What is the Lorentz force?

The force exerted on a charged particle travelling along an electric field and magnetic field is known as the Lorentz force.

Which devices use the Lorentz force? 

Lorentz force is used in magnetrons, cyclotrons and other circular route particle accelerators, mass spectrometers, velocity filters, and Lorentz force velocimetry.

Explain the working of Lorentz transformation.

A Lorentz transformation is the relationship between two different coordinate frames that are travelling apart from one another at a constant speed.

State a few effects of Lorentz’s transformation?

The Lorentz transformation has several noticeable effects, but one of them is the requirement to give up simultaneity as a universal concept. Also relative is simultaneity.

Give a few applications of Lorentz transformation?

Three accurate predictions of Lorentz transformations are as follows:

1. Length Contraction
2. Time Dilation
3. Relativity of Simultaneity

What is time dilation? 

Assume, a clock that is watched over by two distinct people. One  observer is travelling at the speed of light, with one being at rest. Then, time dilation is the existence of a time discrepancy between the two clocks.

What is the Lorentz transformation equation?

The Lorentz transformation equations consist of equations for time dilation, length contraction, and the relativistic addition of velocities. The primary equations are used to transform coordinates and velocities between inertial frames.

How are Lorentz transformations different from Galilean transformations?

Lorentz transformations differ from Galilean transformations, which are used in classical mechanics, particularly at low speeds. Lorentz transformations account for the constancy of the speed of light and the relativity of simultaneity.

What is the significance of Lorentz transformations?

Lorentz transformations are fundamental to understanding the behavior of space and time in special relativity. They provide a framework for reconciling the observations of different observers in relative motion and explain phenomena such as time dilation and length contraction.

Do Lorentz transformations only apply to objects moving at relativistic speeds?

Lorentz transformations apply to all objects moving relative to each other, regardless of speed. However, their effects become more pronounced as velocities approach the speed of light, leading to significant differences in observations between inertial frames.

Are Lorentz transformations reversible?

Yes, Lorentz transformations are reversible, meaning they can be applied in both directions to transform coordinates and velocities between inertial frames. This reversibility ensures consistency and symmetry between observations in different frames.

What are some practical applications of Lorentz transformations?

Lorentz transformations have practical applications in fields such as particle physics, astrophysics, and engineering. They are used to calculate relativistic effects in particle accelerators, understand the behavior of high-speed cosmic objects, and design spacecraft and communication systems.