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Given a square matrix of order n*n, you have to interchange the elements of both diagonals. Input : matrix[][] = {1, 2, 3, 4, 5, 6, 7, 8, 9} Output : matrix[][] = {3, 2, 1, 4, 5, 6, 9, 8, 7} Input : matrix[][] = {4, 2, 3, 1, 5, 7, 6, 8, 9, 11, 10, 12, 16, 14, 15, 13} Output : matrix[][] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 11, 14, 15, 16}
Explanation : Idea behind interchanging diagonals of a square matrix is simple. Iterate from 0 to n-1 and for each iteration you have to swap a[i][i] and a[i][n-i-1].
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Output: 6 5 4 1 2 3 9 8 7 Time Complexity: O(N*N), as we are using nested loops for traversing the matrix. Auxiliary Space: O(1), as we are not using any extra space. Please refer complete article on Program to Interchange Diagonals of Matrix for more details! |
Reffered: https://www.geeksforgeeks.org
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Type: | Geek |
Category: | Coding |
Sub Category: | Tutorial |
Uploaded by: | Admin |
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