Bx
By
Bz

So, 

A.B = A_xB_x +A_yB_y + A_zB_z

Check: Product of Vectors

Properties of Scalar Multiplication of Vectors

1. Commutative Properties of Scalar Multiplication:

   If a and b are two vectors then:

   a.b = b.a

   As,

   a.b = |a||b| cos θ , and

   b.a = |b||a| cos θ

   So  a.b = b.a

2. Distributive Over Vector Addition:

    If a, b ,c are vector then,    

    a.(b+c) = a.b + a.c

3. Associative Property:

    If a is a vectors and  c, d are scalars then,

    c (da) = (cd) a

4. Identity Property:

    If a is a vector then,

    1⋅a = a

5. Multiplicative Property of 0:

   If a is a vector then,

   0 (a)=0

Sample Problems on Scalar Product of Vectors

Problem 1: Find the scalar product of vector A= 2i + 5j +3k and vector B= 3i + j +2k.

Solution:

A. B = (2 * 3) + (5 * 1) +(3 * 2)

        = 6 + 5 + 6

        = 17 

Problem 2: A particle covers a displacement from position 2i + j + 2k to 3i + 2j +5k due to uniform force of ( 7i + 5j +2k) N. If the displacement is in mitres calculate the work done. 

Solution: 

Given,

Final position P2 = 3i + 2j +5k

Initial position P1 = 2i +j +2k

Force F = ( 7 i + 5 j + 2 k ) N

So  

The displacement D  = P2 – P1

D = ( 3 – 2 ) i + ( 2 -1 ) j + ( 5 – 2 ) k

   = i + j + 3k

Work done = F . D

= ( 7 i + 5 j + 2 k ) . ( i + j  +  3k )

= ( 7*1 ) + ( 5*1 ) + ( 2*3 )

= 7 + 5 + 6

= 18  J

Problem 3: Find the value of m such that  vectors A = 2 i + 3j + k and B = 3 i + 2 j + mk may be perpendicular.

Solution:

Given,

A and B are perpendicular

so A . B = 0 

( 2 i + 3j + k ) . (  3i + 2j + mk ) = 0

( 2 * 3 ) + ( 3 * 2 ) + ( 1 * m ) = 0

6 + 6 + m = 0

12 + m = 0

m = -12 

Problem 4: Prove that vectors U = 2i + 3j + k and V = 4i – 2j + 2k are perpendicular to each other.

Solution:

Given,

U = 2i + 3j + k

V = 4i – 2j + 2k 

to prove U and V are perpendicular to each other

U . V = ( 2i + 3j + k ) . ( 4i – 2j – 2k )

         = ( 2 * 4 ) + ( 3 * -2 ) + ( 1 * -2 )

         = 8 – 6 – 2

         = 0

we know that if scalar product of two vectors is 0 then they are perpendicular to each other.

U . V = 0 so, U and V are perpendicular to each other

Hence proved  

Problem 5: Prove that vectors A = 4ax -2ay – az and B = ax + 4ay  -az are perpendicular to each other.

Solution:

|A|=√(4)^2 +(-2)^2 + (-1)^2 =√21

|B| = √(1)^2+(4)^2+(-1)^2 = √18

A . B = (4ax -2ay – az) . (ax + 4ay  -az)

        = 4 -8 + 4 

        =0

|A| |B| cos ∅ = 0

cos ∅ = 0

so ∅ = 90 °

Hence proved.

Applications of Scalar Product

The scalar product, also known as the dot product, serves multiple purposes in vector theory, including:

1. Projection of a Vector: The scalar product is essential for computing the projection of one vector onto another. Specifically, the projection of vector a onto vector b can be expressed as (a·b)/|b|, while the projection of vector b onto vector a is (a·b)/|a|.
2. Scalar Triple Product: The scalar product also plays a role in determining the scalar triple product of three vectors. The formula for this is a·(b × c) = b·(c × a) = c·(a × b), illustrating its cyclic nature.
3. Angle Between Two Vectors: The scalar product is used to calculate the angle between two vectors. This is done using the cosine formula: cos(θ) = (a·b)/( |a| |b| ), which relates the dot product of the vectors to the product of their magnitudes and the cosine of the angle between them.

Scalar Product Properties

Having grasped the concept of scalar product, let’s examine some key properties of the scalar product of vectors ???? and ???? that are useful in problem-solving:

1. Commutative Property: The scalar product is commutative, meaning ????⋅????=????⋅????.
2. Distributive Property: The scalar product obeys the distributive law:
   • ????⋅(????+????)=????⋅????+????⋅????
   • (????+????)⋅????=????⋅????+????⋅????
   • ????⋅(????−????)=????⋅????−????⋅????
   • (????−????)⋅????=????⋅????−????⋅????
3. Scalar Multiplication: The scalar product is consistent with scalar multiplication:
   • (????1????)⋅(????2????)=????1????2(????⋅????)
4. Orthogonality: Two vectors are orthogonal if their scalar product is zero, i.e., vectors ???? and ???? are orthogonal if ????⋅????=0.

Scalar Product – FAQs

What is a scalar product in vectors?

The scalar product, also known as the dot product, is an operation that combines two vectors to produce a scalar. It is calculated by multiplying corresponding components of each vector and summing those products.

How do you calculate the scalar product?

To calculate the scalar product of two vectors, multiply their corresponding components and then add up those products. The formula is ????⋅????=????₁????₁+????₂????₂+????₃????​ for vectors in three-dimensional space.

Is the scalar product commutative?

Yes, the scalar product is commutative. For any two vectors ???? and ????, the scalar product ????⋅???? is equal to ????⋅????.

What does the scalar product tell you about two vectors?

The scalar product provides insights into the geometric relationship between two vectors, specifically their angle. If the scalar product is zero, the vectors are orthogonal (perpendicular). The result can also indicate the degree to which vectors align directionally.

How does the distributive property apply to scalar products?

The scalar product follows the distributive property, allowing for expansion:

• ????⋅(????+????)=????⋅????+????⋅????
• (????−????)⋅????=????⋅????−????⋅????

Can scalar multiplication affect the scalar product of two vectors?

Yes, scalar multiplication affects the scalar product. Multiplying a vector by a scalar before taking the dot product with another vector scales the result by that scalar:

• (????????)⋅????=????(????⋅????)

What are practical applications of scalar products?

Scalar products are used in physics to calculate work done (force applied in the direction of displacement), in computer graphics to determine lighting intensity (angle between light source and surfaces), and in data analysis to measure similarity between datasets.