In this article, we will be looking at the different approaches to get the list of the files in the given directory in the sorted order of size in the Python programming language.

The two different approaches to get the list of files in a directory are sorted by size is as follows:

• Using os.listdir() function
• Using glob() functions 

Method 1: Using os.listdir() function

os.listdir() method in Python is used to get the list of all files and directories in the specified directory. If we don’t specify any directory, then a list of files and directories in the current working directory will be returned.

Syntax: os.listdir(path)

Parameters: path (optional) : path of the directory

Return: This method returns the list of all files and directories in the specified path. The return type of this method is list.

In this method, we will create a list of filenames in a folder sorted by file size. We will pass lambda x: os.stat(os.path.join(dir_name, x)).st_size as the key argument to the sorted() function which will sort the files in directory by size.

Output:

366  --> descript.ion
1688  --> readme.txt
3990  --> License.txt
15360  --> Uninstall.exe
48844  --> History.txt
50688  --> 7-zip32.dll
78336  --> 7-zip.dll
108074  --> 7-zip.chm
186880  --> 7zCon.sfx
205824  --> 7z.sfx
468992  --> 7z.exe
581632  --> 7zG.exe
867840  --> 7zFM.exe
1679360  --> 7z.dll

Method 2: Using glob() function

In python programming language we have the glob module which provides a function called glob() which is used to find files or directories in a given directory based on the matching pattern. Using the glob() function we can use wildcards and regular expression to match and find few files in a directory or all files in a directory. In this method, we will use glob() function to get a list of all files in a directory along with the size. The steps are as follows,

First, we will get list of all files in a directory using glob(), then we will sort the list of files based on the size of files using sorted() function. 

We will use os.stat(file_path).st_size to fetch the file size from stat object of file. Then we will pass the encapsulated size in a lambda function as the key argument in the sorted() function.

Output:

366  --> C:/Program Files/7-Zip\descript.ion
1688  --> C:/Program Files/7-Zip\readme.txt
3990  --> C:/Program Files/7-Zip\License.txt
15360  --> C:/Program Files/7-Zip\Uninstall.exe
48844  --> C:/Program Files/7-Zip\History.txt
50688  --> C:/Program Files/7-Zip\7-zip32.dll
78336  --> C:/Program Files/7-Zip\7-zip.dll
108074  --> C:/Program Files/7-Zip\7-zip.chm
186880  --> C:/Program Files/7-Zip\7zCon.sfx
205824  --> C:/Program Files/7-Zip\7z.sfx
468992  --> C:/Program Files/7-Zip\7z.exe
581632  --> C:/Program Files/7-Zip\7zG.exe
867840  --> C:/Program Files/7-Zip\7zFM.exe
1679360  --> C:/Program Files/7-Zip\7z.dll