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Python | SymPy combinatorics.next_lex() method

With the help of sympy.combinatorics.partitions.IntegerPartition().next_lex() method, we can get the next partition of integer n in lexical order by using sympy.combinatorics.partitions.IntegerPartition().next_lex() method.

Syntax : sympy.combinatorics.partitions.IntegerPartition().next_lex()

Return : Return the lexical value of next partition of integer n.

Example #1 :
In this example we can see that by using sympy.combinatorics.partitions.IntegerPartition().next_lex() method, we are able to get the lexical value of next partition of integer n.




# import sympy and IntegerPartition
from sympy.combinatorics.partitions import IntegerPartition
from sympy import *
    
# Using sympy.combinatorics.partitions.IntegerPartition().next_lex() method
gfg = IntegerPartition([1, 2, 3])
    
print(gfg.next_lex())

Output :

[3, 3]

Example #2 :




# import sympy and IntegerPartition
from sympy.combinatorics.partitions import IntegerPartition
from sympy import *
    
# Using sympy.combinatorics.partitions.IntegerPartition().next_lex() method
gfg = IntegerPartition([1, 2, 3, 4, 3, 2, 1])
    
print(gfg.next_lex())

Output :

[4, 3, 3, 2, 2, 2] 




Reffered: https://www.geeksforgeeks.org

Python

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