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start multiple bash processes and wait for all to complete Code Example
start multiple bash processes and wait for all to complete 
#!/bin/bash

FAIL=0

echo "starting"

./sleeper 2 0 &
./sleeper 2 1 &
./sleeper 3 0 &
./sleeper 2 0 &

for job in `jobs -p`
do
echo $job
    wait $job || let "FAIL+=1"
done

echo $FAIL

if [ "$FAIL" == "0" ];
then
echo "YAY!"
else
echo "FAIL! ($FAIL)"
fi
Source: stackoverflow.com



Shell

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Type:
 Code Example
Category:
 Coding
Sub Category:
 Code Example
Uploaded by:
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