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bash echo a checkMark based on condition Code Example
bash echo a checkMark based on condition 
#!/bin/bash

echo -e "\xE2\x9C\x94 existing"
echo -e "\xE2\x9D\x8C missing"
Source: unix.stackexchange.com



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Type:
 Code Example
Category:
 Coding
Sub Category:
 Code Example
Uploaded by:
 Admin
Views:
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