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how to get the filename without extension Code Example
how to get the filename without extension 
basename -a `ls`

ss=$(basename -a `ls`)
echo $ss

basename --help
Usage: basename NAME [SUFFIX]
  or:  basename OPTION... NAME...
Print NAME with any leading directory components removed.
If specified, also remove a trailing SUFFIX.

Mandatory arguments to long options are mandatory for short options too.
  -a, --multiple       support multiple arguments and treat each as a NAME
  -s, --suffix=SUFFIX  remove a trailing SUFFIX
  -z, --zero           separate output with NUL rather than newline
      --help     display this help and exit
      --version  output version information and exit

Examples:
  basename /usr/bin/sort          -> "sort"
  basename include/stdio.h .h     -> "stdio"
  basename -s .h include/stdio.h  -> "stdio"
  basename -a any/str1 any/str2   -> "str1" followed by "str2"

GNU coreutils online help: <http://www.gnu.org/software/coreutils/>



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Category:
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Sub Category:
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