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async fetch api call Code Example
async function fetchJson 
async function getUserAsync(name) 
{
  let response = await fetch(`https://api.github.com/users/${name}`);
  let data = await response.json()
  return data;
}

getUserAsync('yourUsernameHere')
  .then(data => console.log(data));
Source: dev.to
async fetch api call 
async function getUserAsync(name) {
  try{
    let response = await fetch(`https://api.github.com/users/${name}`);
    return await response.json();
  }catch(err){
    console.error(err);
    // Handle errors here
  }
}
fetch js async await 
async function getData() {
   const response = await fetch('https://jsonplaceholder.typicode.com/users');
            const data = await response.json();
            const {
                id = data[1]['id'],
                name = data[1]['name'],
                username = data[1]['username'],
                email = data[1]['email'],
                address = data[1]['address']
            } = data
            console.log(data)
            console.log(`ID: ${id}`);
            console.log(`Name: ${name}`)
            console.log(`Email: ${email}`)
            console.log(`Username: ${username}`)
            console.log(address)
            console.log('Street: ' + address.street)
            console.log(address.suite)
        }
	getData();



Javascript

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Type:
 Code Example
Category:
 Coding
Sub Category:
 Code Example
Uploaded by:
 Admin
Views:
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Horje