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check if array exists in another array javascript Code Example
javascript array includes another array 
const array1= ["cheese", "dough", "sauce", "pepperoni"]
const array2= ["mozzarella", "peppers", "chicken", "cheese"]

const isIncluded =  array1.some(value => array2.includes(value))
// true

const values = array1.filter(value => array2.includes(value))
// "cheese"
Source: dev.to
javascript check if elements of one array are in another 
const found = arr1.some(r=> arr2.includes(r))
Source: stackoverflow.com
How to check if array includes a value from another array in JavaScript 
// How to check if array includes a value from another array in JavaScript
const includesAny = (arr, values) => values.some(v => arr.includes(v));
includesAny([1, 2, 3, 4], [2, 9]); // true
includesAny([1, 2, 3, 4], [8, 9]); // false
Source: www.30secondsofcode.org
javascript check if array is subset of another 
let superSet = ['B', 'C', 'A', 'D'];
let subSet = ['D', 'C'];
let mixedSet = new Set([...superSet, ...subSet]);
let isSubset = mixedSet.size == superSet.length
check if array exists in another array javascript 
const found = arr1.some(r=> arr2.indexOf(r) >= 0)
Source: stackoverflow.com



Javascript

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Type:
 Code Example
Category:
 Coding
Sub Category:
 Code Example
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