Program to print the number of days in a given year - Coding

Write a program to print the number of days in a given year.

Examples:

Input: 2023
Output: 365
Explanation: The year 2023 is not a leap year, therefore the number of days are 365.

Input: 2024
Output: 366
Explanation: The year 2024 is a leap year, therefore the number of days are 366.

Approach: To solve the problem, follow the below idea:

To determine the number of days in a given year, you need to consider whether the year is a leap year or not. A year is a leap year if the following conditions are satisfied:

The year is multiple of 400.

The year is a multiple of 4 and not a multiple of 100.

So, if it is a leap year the year contains 366 days and if not a leap year, then no. of days in a year are 365.

Below is the implementation of the above approach:

C++

#include <iostream>
using namespace std;
 
bool isLeapYear(int year)
{
    // Leap year is divisible by 4, but not divisible by 100
    // unless divisible by 400
    return (year % 4 == 0 && year % 100 != 0)
        || (year % 400 == 0);
}
 
int main()
{
    int year = 2024;
 
    // Check if the year is a leap year
    if (isLeapYear(year)) {
        cout << "Leap year. It has 366 days." << endl;
    }
    else {
        cout << "Common year. It has 365 days." << endl;
    }
 
    return 0;
}

Java

public class LeapYearChecker {
 
    // Function to check if a year is a leap year
    static boolean isLeapYear(int year) {
        // Leap year is divisible by 4, but not divisible by 100 unless divisible by 400
        return (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);
    }
 
    public static void main(String[] args) {
        // Set the year to be checked
        int year = 2024;
 
        // Check if the year is a leap year
        if (isLeapYear(year)) {
            System.out.println("Leap year. It has 366 days.");
        } else {
            System.out.println("Common year. It has 365 days.");
        }
    }
}

Python3

def is_leap_year(year):
    # Leap year is divisible by 4, but not divisible by 100
    # unless divisible by 400
    return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)
 
if __name__ == "__main__":
    year = 2024
 
    # Check if the year is a leap year
    if is_leap_year(year):
        print(f"Leap year. It has 366 days.")
    else:
        print(f"Common year. It has 365 days.")

C#

using System;
 
class LeapYearCheck
{
    // Function to check if a year is a leap year
    static bool IsLeapYear(int year)
    {
        // Leap year is divisible by 4, but not divisible by 100
        // unless divisible by 400
        return (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);
    }
 
    static void Main()
    {
        int year = 2024;
 
        // Check if the year is a leap year
        if (IsLeapYear(year))
        {
            Console.WriteLine("Leap year. It has 366 days.");
        }
        else
        {
            Console.WriteLine("Common year. It has 365 days.");
        }
    }
}

Javascript

// Function to check if a year is a leap year
function is_leap_year(year) {
    // Leap year is divisible by 4, but not divisible by 100 unless divisible by 400
    return (year % 4 === 0 && year % 100 !== 0) || (year % 400 === 0);
}
 
// Main Program
const year = 2024;
 
// Check if the year is a leap year
if (is_leap_year(year)) {
    console.log(`Leap year. It has 366 days.`);
} else {
    console.log(`Common year. It has 365 days.`);
}

Output

Leap year. It has 366 days.

Time Complexity: O(1)
Auxiliary space: O(1)

Reffered: https://www.geeksforgeeks.org

Android

Related
Program to count the number of months between given two years
How to Use Emergency SOS on Android and iPhone?
Program to check a number is divisible by 5 or not
How to Develop Android Apps with Ionic and Capacitor?
Longest mutation sequence

Type:	Geek
Category:	Coding
Sub Category:	Tutorial
Uploaded by:	Admin
Views:	13