Table of Content

• What are Trigonometric Equations?
• Trigonometric Equations Examples
• Solving Trigonometric Equations
• General Solutions Trigonometric Equations
• Proof of Solutions of Trigonometric Equations
• Trigonometric Equations Formulas
• Trigonometric Equations Solved Examples
• Trigonometric Equations Class 11
• Trigonometric Equations Questions for Practice

Trigonometric Equations	General Solutions
sin θ = 0	θ = nπ
cos θ = 0	θ = (nπ + π/2)
tan θ = 0	θ = nπ
sin θ = 1	θ = (2nπ + π/2) = (4n+1)π/2
cos θ = 1	θ = 2nπ
sin θ = sin α	θ = nπ + (-1)nα, Where α ∈ [-π/2, π/2]
cos θ = cos α	θ = 2nπ ± α, Where α ∈ (0, π]
tan θ = tan α	θ = nπ + α, Where α ∈ (-π/2 , π/2]
sin 2θ = sin 2α	θ = nπ ± α
cos 2θ = cos 2α	θ = nπ ± α
tan 2θ = tan 2α	θ = nπ ± α

If α is supposed to be the least positive number that satisfies two specified trigonometrical equations, then the general value of θ will be 2nπ + α.

Principle Solution of Trigonometric Equations

The principal solution of a trigonometric equation refers to the solution that falls within a specific interval, typically between 0° and 360° or 0 and 2π radians. This solution represents the primary or fundamental solution of the equation, and it is often used as a reference point when finding other solutions.

Proof of Solutions of Trigonometric Equations

Let us now use theorems to demonstrate these solutions i.e.,

• sin x = sin y implies x = nπ + (–1)ⁿy, where n ∈ Z
• cos x = cos y, which implies x = 2nπ ± y, where n ∈ Z
• tan x = tan y implies x = nπ + y, where n ∈ Z

Let’s discuss these theorems in detail.

Theorem 1: If x and y are real integers, sin x = sin y implies x = nπ + (–1)ⁿy, where n ∈ Z

Proof: Consider the following equation: sin x = sin y. Let’s try to solve this trigonometric equation in general.

sin x = sin y 

⇒ sin x – sin y = 0 

⇒ sin x – sin y = 0 

⇒ 2cos (x + y)/2 sin (x – y)/2 = 0 

⇒ cos (x + y)/2 = 0 or sin (x – y)/2 = 0

Taking the common answer from both requirements, we obtain:

x = nπ + (-1)ny, where n ∈ Z

Theorem 2: For any two real integers x and y, cos x = cos y, which implies x = 2nπ ± y, where n ∈ Z.

Proof: Likewise, the generic solution of cos x = cos y is: 

cos x – cos y = 0.

⇒ 2sin (x + y)/2 sin (y – x)/2 = 0

⇒ sin (x + y)/2 = 0 or sin (x – y)/2 = 0

⇒ (x + y)/2 = nπ or (x – y)/2 = nπ

Taking the common answer from both criteria yields:

x = 2nπ± y, where n ∈ Z

Theorem 3: Show that tan x = tan y implies x = nπ + y, where n ∈ Z if x and y are not odd multiples of π/2.

Proof: Similarly, we may utilise the conversion of trigonometric equations to obtain the solution to equations involving tan x or other functions.

In other words, if tan x = tan y,

then, sin x cos x = sin y cos y 

⇒ sin x cos y – sin y cos x 

⇒ sin x cos y – sin y cos x = 0 

⇒ sin (x – y) = 0

As a result, x – y =nπ or x = nπ + y, where n ∈ Z.

Trigonometric Equations Formulas

For solving other trigonometric equations, we use some of the conclusions and general solutions of the fundamental trigonometric equations. The following are the outcomes:

• For any two real integers, x and y, sin x = sin y means that x = nπ + (-1)ⁿ y, where n ∈ Z.
• For any two real integers, x and y, Cos x = cos y implies x = 2nπ ± y, where n ∈ Z.
• If x and y are not odd multiples of π/2, then tan x = tan y implies that x = nπ + y, where n ∈ Z.

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Trigonometric Equations Solved Examples

Example 1: Determine the primary solution to the trigonometric equation tan x = -√3

Solution:

We have tan x = -√3 here, and we know that tan /3 = √3. So there you have it.

tan x = -√3

⇒ tan x = – tan π/3

⇒ tan x = tan(π – π/3) Alternatively, tan x = tan(2π – π/3)

⇒ tan x = tan 2π/3 OR tan x = tan 5/3.

As a result, the primary solutions of tan x = -√3 are 2π/3 and 5π/3

The primary answers are x = 2π/3 and x = 5π/3.

Example 2: Find sin 2x – sin 4x + sin 6x = 0

Solution:

Given: sin 2x – sin 4x + sin 6x = 0.

⇒sin 2x + sin 6x – sin 4x = 0

⇒2sin 4x.cos 2x – sin 4x = 0

⇒sin 4x (2cos 2x – 1) = 0

⇒sin 4x = 0 or cos 2x = 1/2

⇒4x = nπ or 2x = 2nπ ± π/3

As a result, the general solution to the above trigonometric problem is as follows:

⇒x = nπ/4 or nπ ± π/6

Example 3: Determine the primary solution to the equation sin x = 1/2.

Solution:

We already know that

sin π/6 = 1/2

sin 5π/6 = sin (π – π/6)

= sin π/6 = 1/2

As a result, the primary answers are x =π/6 and x = 5π/6.

Example 4: Determine the answer to cos x = 1/2.

Solution:

In this example, we’ll use the general solution of cos x = 1/2. Because we know that cos π/3 = 1/2, we have 

cos x = 1/2 

cos x = cos π/3 

x = 2nπ + (π/3), where n ∈ Z —- [With Cosθ = Cosα, the generic solution is θ = 2nπ + α, where n ∈ Z]

As a result, cos x = 1/2 has a generic solution of x = 2nπ + (π/3), where n ∈ Z.

Example 5: Determine the primary solutions to the trigonometric equation sin x = 3/2.

Solution:

To obtain the primary solutions of sin x = √3/2, we know that sin π/3 = √3/2 and sin (π – π/3) = √3/2

sin π/3 = sin 2π/3 = √3/2

We can discover additional values of x such that sin x = √3/2, but we only need to find those values of x where x is between [0, 2π] since a primary solution is between 0 and 2π.

As a result, the primary solutions of sin x = √3/2 are x = π/3 and 2π/3.

Trigonometric Equations Class 11

In Class 11, trigonometric equations form a significant part of the mathematics curriculum, focusing on understanding how to solve equations involving trigonometric functions. Learning to solve these equations involves a combination of analytical skills, use of algebraic methods, and sometimes graphical interpretations. The study of trigonometric equations in Class 11 sets the foundation for further exploration in calculus and advanced trigonometry in higher education.

Also Check: Trigonometric Functions Class 11 Notes

Trigonometric Equations Questions for Practice

Problem 1: Solve for x in the equation: sin(x) = 1/2

Problem 2: Find all solutions for x in the equation: 2 cos(2x) = 1

Problem 3: Determine the solutions for x in the equation: tan(x) = -√3

Problem 4: Solve for x in the equation: 3 sin(x) – 4 cos(x) = 0

Problem 5: Find the solutions for x in the equation: 2 sin(2x) + 1 = 0

Problem 6: Solve for x in the equation: cot(x) = 1

Problem 7: Determine all solutions for x in the equation: 3 sin(x) + 2 cos(x) = 0

Problem 8: Find the values of x that satisfy the equation: tan(2x) = 1

Problem 9: Solve for x in the equation: sec(x) = -2

Problem 10: Find all solutions for x in the equation: 4 sin(3x) = 1

FAQs on Trigonometric Equations

Define Trigonometric Equations.

Trigonometric equations are similar to algebraic equations in that they might be linear, quadratic, or polynomial equations. In trigonometric equations, the trigonometric ratios Sinθ, Cosθ, Tanθ are used to denote the variables.

Give Some Examples of Trigonometric Equations.

The following are some instances of trigonometric equations:

• 2 Cos2x + 3 Sinx = 0 
• Cos4x = Cos2x 
• Sin2x – Sin4x + Sin6x = 0

Which three trigonometric equations are there?

Sinθ, Cosθ, and Tanθ are the three major functions in trigonometry.

What is Sin Inverse?

The arcsin function is the inverse of the sin function. Sin, on the other hand, will not be invertible since it is not injective, and so it is not mixed (invertible). Furthermore, in order to obtain the arcsine function, the domain of sine must be limited to [−π/2,π/2].

How to Find Solutions of Trigonometric Equations?

To find solutions to trigonometric equations, use identities and algebraic techniques to isolate the variable. Then, apply inverse trig functions and consider the unit circle.

How do I solve Trigonometric Equations in Class 11 Math?

To solve trigonometric equations in Class 11 math:

• Isolate the trigonometric function on one side.
• Apply trigonometric identities and simplify the equation.
• Solve for the variable using inverse trigonometric functions.
• Check for extraneous solutions.
• State the solution with appropriate constraints.

What is the Principal Solution of a Trigonometric Equation?

The principal solution of a trigonometric equation is the solution within the principal interval, typically in radians: [-π, π] for cosine, or [0, 2π] for the sine and tangent function.

What Are Trigonometric Identities, and How Are They Used in Solving Equations?

Trigonometric identities are equations involving trig functions, and these are used to simplify and solve trigonometric equations by manipulating expressions.

How Do I Find All Solutions of a Trigonometric Equation?

To find all solutions of a trigonometric equation, you can first find the principal solution and then use the periodicity of trigonometric functions to add integer multiples of the period.